3construchauteur
Date: 23 Mars 2015

ABC triangle donné, D un point de (AB)
Construire ADE de même aire que ABC
donc de hauteur h=AB x CH / AD
On construit G tel que AG/CH=AB/AD
 

hauteur

triangle

B = (4.46, -1.9)
A = (-0.74, -1.96)
j = Line(A, B)
D = Point(j)
a = Segment(A, B)
d = OrthogonalLine(A, a)
C = (2.56, 5.28)
e = OrthogonalLine(C, j)
H = Intersect(j, e)
f = OrthogonalLine(C, d)
F = Intersect(d, f)
g = Segment(F, C)
α = Angle(H, A, F)
β = Angle(B, H, C)
h = Segment(F, D)
i = Line(H, h)
b = Line(B, h)
poly1, a_1, c, b_1 = Polygon(C, B, A)
G = Intersect(d, b)
k = Segment(G, B)
l = Line(G, j)
E = Point(l)
poly2, j_1, a_2, e_1 = Polygon(A, E, D)
p: a + a_1 + b_1
q: a_2 + e_1 + j_1
m = Segment(H, C)
n = Segment(A, F)
o = false
r = false
texte2: "aire(ABC)=" + poly1 + ", aire(ADE)=" + poly2 + ""